Air is a mixture of a number of gases. The ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The total pressure of air over water is $10\ atm$.The partial pressure of nitrogen is $P_{N_2} = \frac{79}{100} 	imes 10\ atm = 7.9\ atm = 7.9

Vedclass · Accepted Answer

$1 : 2$

Vedclass · Answer

(A) The total pressure of air over water is $10\ atm$.The partial pressure of nitrogen is $P_{N_2} = \frac{79}{100} 	imes 10\ atm = 7.9\ atm = 7.9 	imes 760\ mm\ Hg = 6004\ mm\ Hg$.The partial pressure of oxygen is $P_{O_2} = \frac{20}{100} 	imes 10\ atm = 2.0\ atm = 2.0 	imes 760\ mm\ Hg = 1520\ mm\ Hg$.According to Henry's law,$P = K_H 	imes X$,where $X$ is the mole fraction of the gas in the solution.$X_{N_2} = \frac{P_{N_2}}{K_H(N_2)} = \frac{6004}{6.51 	imes 10^7} = 9.22 	imes 10^{-5}$.$X_{O_2} = \frac{P_{O_2}}{K_H(O_2)} = \frac{1520}{3.30 	imes 10^7} = 4.60 	imes 10^{-5}$.The mole ratio of dissolved gases is $\frac{X_{O_2}}{X_{N_2}} = \frac{4.60 	imes 10^{-5}}{9.22 	imes 10^{-5}} \approx 0.5 = \frac{1}{2}$.

Similar Questions

Why is a soda water bottle kept in a cold place?

The Henry's law constant for the dissolution of a gas in an aqueous medium is $3 \times 10^2 \ atm$. At what partial pressure of the gas will the molality of the gas in the aqueous solution be $\frac{5}{9} \ m$?

At $293 \ K$,the Henry law constant in water for $N_2$ and $O_2$ are $76.48 \ kbar$ and $34.86 \ kbar$ respectively. What is the ratio of mole fractions of $N_2$ and $O_2$ in water? (Assume partial pressures of $N_2$ and $O_2$ are the same at $293 \ K$)

$K_H$ is Henry's constant and has the unit

Give an example of a solid solution in which the solute is a gas.

Vedclass Test Series

Exam Paper Generator

Online Exam Module